[see also: alone, just, merely, single, solely]
Assume that the only functions v, w satisfying (2) are v=w=0.
Then the one and only integral curve of L starting from x is the straight line l.
Here {x} is the set whose only member is x.
The problem is to move all the disks to the third peg by moving only one at a time.
However, only 5 of these are distinct.
Note that F is defined only up to an additive constant.
We need only consider the case...... [Or: We only need to consider]
The proof will only be indicated briefly.
We have to change the proof of Lemma 3 only slightly.
To prove (8), it only remains to verify that......
Thus X assumes the values 0 and 1 only.
Only for x=1 does the limit exist. [Note the inversion.]
If we know a covering space E of X then not only do we know that...... but we can also recover X (up to homeomorphism) as E/G.
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