[see also: calculation]
Incidentally, our computation shows that......
A short computation shows that......
It is sufficient to make the computation for T.
In fact, the computation for A becomes somewhat simpler.
One of the appealing aspects of the spectral set γ is that it readily lends itself to explicit computation.
This proves one half of (2); the other half is a matter of direct computation.
However, one needs to perform computations which become time consuming as n increases.
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